查询结果输出时要求按“总评成绩”降序排列,相同者按“性别”升序,正确的子句是_________。
A.ORDER BY 总评成绩 DESC,性别
B.ORDER BY 总评成绩,性别 DESC
C.ORDER BY 总评成绩 DESC,性别 DESC
D.ORDER BY 总评成绩 ASC,性别 DESC
- · 有6位网友选择 A,占比54.55%
- · 有5位网友选择 B,占比45.45%
A.ORDER BY 总评成绩 DESC,性别
B.ORDER BY 总评成绩,性别 DESC
C.ORDER BY 总评成绩 DESC,性别 DESC
D.ORDER BY 总评成绩 ASC,性别 DESC
A. ORDER BY 工资
B. ORDER BY 工资 desc
C. ORDER BY 工资 asc
D. ORDER BY 工资 dictinct
A、select * from student order by sdept , sage
B、select sname, sdept, sage from student order by sdept , sage
C、select sname, sdept, sage from student order by sdept desc , sage
D、select * from student order by sdept desc, sage
A、select top 3 * from 学生
B、select top 3 from 学生
C、select 3 * from 学生
D、select top 3 * 学生
A、SELECT SNO, SUM (GRADE) AS SUM_GRADE FROM SC GROUP BY SNO ORDER BY SUM_GRADE DESC HAVING COUNT(*) >= 4;
B、SELECT SNO, SUM (GRADE) AS SUM_GRADE FROM SC GROUP BY SNO HAVING COUNT(*)>=4 ORDER BY SUM_GRADE DESC;
C、SELECT SNO, SUM (GRADE) AS SUM_GRADE FROM SC HAVING COUNT(*)>=4 GROUP BY SNO ORDER BY SUM_GRADE DESC;
D、SELECT SNO, SUM (GRADE) AS SUM_GRADE FROM SC ORDER BY SUM_GRADE DESC GROUP BY SNO HAVING COUNT(*)>=4;
A、SELECT S#,SUM(GRADE) FORM SC GROUP BY S# HAVING COUNT(*)>=4;
B、SELECT S#,SUM(GRADE) FORM SC GROUP BY S# HAVING COUNT(*)>=4 ORDER BY SUM(GRADE) DESC;
C、SELECT S#,SUM(GRADE) FROM SC WHERE GRADE>=60 GROUP BY S# HAVING COUNT(*)>=4 ORDER BY SUM(GRADE) DESC;
D、SELECT S#,SUM(GRADE) FROM SC GROUP BY S# HAVING GRADE>=60 AND COUNT(*)>=4 ORDER BY SUM(GRADE) DESC;
A、4,8
B、1,5,6,7
C、2,3,6,8
D、1,5,7
A、UPDATE 选课 SET 成绩=成绩+10 WHERE 课号=‘1002’;
B、UPDATE 选课 SET 成绩=成绩+10 WHERE 课号=1002;
C、SET 选课 UPDATE 成绩=成绩+10 WHERE 课号=‘1002’;
D、UPDATE 选课 SET 成绩+10 WHERE 课号=‘1002’;
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