[图] 如图所示,根据RIPv1接收路由更新规则分析,路由器...
如图所示,根据RIPv1接收路由更新规则分析,路由器R1和路由器R2执行RIPv1路由协议后,路由器R2生成的路由表正确的是:
A、R 1.0.0.0/8 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0 172.16.0.0/24 is subnetted, 2 subnets C 172.16.10.0 is directly connected, FastEthernet0/0 R 172.16.20.0 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0 R 182.15.0.0/16 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0 R 192.168.10.0/24 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0
B、R 1.1.1.0/8 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0 172.16.0.0/24 is subnetted, 2 subnets C 172.16.10.0 is directly connected, FastEthernet0/0 R 172.16.20.0 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0 R 182.15.0.0/16 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0 R 192.168.10.0/24 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0
C、R 1.0.0.0/8 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0 172.16.0.0/24 is subnetted, 2 subnets C 172.16.10.0 is directly connected, FastEthernet0/0 R 172.16.0.0 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0 R 182.15.0.0/16 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0 R 192.168.10.0/24 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0
D、R 1.0.0.0/8 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0 172.16.0.0/24 is subnetted, 2 subnets C 172.16.0.0 is directly connected, FastEthernet0/0 R 172.16.0.0 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0 R 182.15.0.0/16 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0 R 192.168.10.0/24 [120/1] via 172.16.10.1, 00:00:12, FastEthernet0/0