题目内容
(请给出正确答案)
提问人:网友lixin080108
发布时间:2022-01-24
[主观题]
定黄铁矿石中硫含量,称取样品0.3862g,最后得到BaSO4沉淀0.9321g,计算样品中硫的百分含量
简答题官方参考答案
(由简答题聘请的专业题库老师提供的解答)
换算因素为S/BaSO4=32.07/233.4
=0.1374S%
=0.9321•0.1374/0.3862×100=33.16%
答:此样品含硫为33.16%。
=0.1374S%
=0.9321•0.1374/0.3862×100=33.16%
答:此样品含硫为33.16%。