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CODE SEGMENT ASSUME CS:CODE BEG: XOR BL,BL MOV AH, 1 INT 21H MOV BL, AL MOV CX, 8 LAST: MO
A、继续执行MOV DL,‘1’
B、转去执行LAST
C、转去执行NEXT
D、转去执行LOOP
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![](https://lstatic.shangxueba.com/jiandati/pc/images/no_answer.png)
A、继续执行MOV DL,‘1’
B、转去执行LAST
C、转去执行NEXT
D、转去执行LOOP
阅读下列程序段: DATA SEGMENT STR DB 99,100 DUP () DATA ENDS CODE SEGMENT ASSUME DS:DATA, CS:CODE START: ...... MOV DX, OFFSET STR MOV AH,0AH INT 21H MOV CH,STR+1 MOV CL,STR+2 ...... CODE ENDS END START 此段程序执行后,从键盘输入字符串‘ABCDEFG’,则CH和CL分别是什么?
下列程序执行后,DX寄存器的内容是() CODE SEGMENT ASSUME CS:CODE START: MOV CL,3 MOV DX,0C6H ROL DX,2 ROR DX,CL CODE ENDS END START
A.35
B.63H
C.53H
D.138H
A.0003H
B.0300H
C.0400H
D.0004H
执行下列程序后,(CX)=()。 DATA SEGMENT A DW 1, 2, 3, 4, 5 B DW 5 DATA SEGMENT CODE SEGMENT ASSUME CS: CODE, DS: DATA START: MOV AX, DATA MOV DS, AX LEA BX, A ADD BX, B MOV CX, [BX] MOV AH, 4CH INT 21H CODE ENDS END START
A.400
B.0
C.10
D.100
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