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提问人:网友lixin080108
发布时间:2022-01-24
[主观题]
计算题:HG-2008/18.2-YM2锅炉,额定蒸发量为2008t/h,每小时燃煤消耗量为275.4t,燃煤收到基低位发热量为20525kJ/kg,炉膛容积为16607.4m3,求该炉膛容积热负荷
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已知B=275.4t,Qar’net=20525kJ/kg,V=16607.4m3
qv=BQar’net/V=275400×20525/16607.4=340.365×103kJ/(m3h)
该炉容积热负荷为340.365×103kJ/(m3h)
qv=BQar’net/V=275400×20525/16607.4=340.365×103kJ/(m3h)
该炉容积热负荷为340.365×103kJ/(m3h)