- Please help yourself to the seafood.-().
A.No, I can't
B.Sorry, I can't help
C.Well, seafood don't suit for
D.Thanks, but I don't like the seafood
A.No, I can't
B.Sorry, I can't help
C.Well, seafood don't suit for
D.Thanks, but I don't like the seafood
main()
{int a[]={1,3,5,2,7};
int b[]={5,3,9,4,6};
int c[5],i;
for(i=0;i<5;i++)
c[i]=a[i]*b[i];
for(i=0;i<5;i++)
printf("%d",c[i]);}
程序运行结果是:______
A.i=1 i=2 i=3 i=4
B.i=1 i=1 i=1 i=1
C.i=0 i=1 i=2 i=3
D.i=1 i=2 i=3
已知:关于S i 和C i+1 的逻辑运算式如下:
S i = ((A i XOR B i ) XOR C i
C i+1 = ((A i ANDB i ) OR ((A i XOR B i ) ANDC i ) ,问:
(1) 如果A i = 1,B i = 0,C i = 1,则S i ,C i+1 的值为________。
(A)0,0;
(B)0,1;
(C)1,0;
(D)1,1;
(2) 如果A i = 1,B i = 1,C i = 1,则S i ,C i+1 的值为________。
(A)0,0;
(B)0,1;
(C)1,0;
(D)1,1;
A.for(i=1;i<=10;i=i+1)>
B.for(i=2;i<=20;i=i+2)>
C.for(i=0;i<=9;i=i+1)>
D.for(i=10;i>=1;i=i-1) {循环体;}
A.@for(c(i,j):x(i,j))>100.0001;
B.@sum(c(i,j):x(i,j))>100.0001;
C.@for(a(i):@sum(b(j):x(i,j))>100.0001);
D.@for(b(j):@sum(a(i):x(i,j))>100.0001);
A.i = 5 Do While i > 0 i = i + 1 Loop
B.i = 1 Do i = i + 2 Loop Until i = 10
C.i = 10 Do i = i + 1 Loop Until i > 0
D.i = 6 Do i = i + 2 Loop While i > 2
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