程序执行结果s的值是【】.Private Sub Command l-Click ()I =0DoS= I +SI = I + lLoop Until I >=4
程序执行结果s的值是【 】.
Private Sub Command l-Click ()
I =0
Do
S= I +S
I = I + l
Loop Until I >=4
End Sub
程序执行结果s的值是【 】.
Private Sub Command l-Click ()
I =0
Do
S= I +S
I = I + l
Loop Until I >=4
End Sub
程序执行结果S的值是【 】。 Private Sub Command1_Click() i=0 Do i=i+1 s=i+s Loop Until i>=4 Print s End Sub
9.程序执行结果s的值是 [9] 。
Private Sub Commandl_Click()
i = 0
Do
i = i + l
s = i + s
Loop Until i > = 4
Print s
End Sub
执行下列程序: CLEAR DO A RETURN PROCEDURE A PRIVATE S S=5 DO B ?S RETURN PROCEDURE B S=S+10 RETURN 程序的运行结果为
A.5
B.10
C.15
D.程序错误,找不到变量
下列程序段的执行结果为 Private Sub Command1_Click() a=InputBox("请输入a值") c="您要查询的是" &IIf(a>0,"天气"," ") &IIf(a<0,"电话号码"," ") &IIf(a=0,"邮编"," ") Text1.Text=c End Sub程序运行后,如果从键盘上输入"16",则在文本框显示的内容是______。
A.您要查询的是天气
B.您要查询的是邮编
C.您要查询的是电话号码
D.False
为计算10+21+22+23+24+…+210的值,并把结果显示在文本框Textl中,若编写如下事件过程:
Private Sub Commandl_Click()
Dim a%,s%,k%
S=1
a=2
FOr k=2 To 10
a=a*2
S=S+a
Next k
Text1,Text=s
End Sub
执行此事件过程后发现结果是错误的,为能够得到正确结果,应做的修改是
A.把s=1改为s=0
B.把For k=2 TO 10改为For k=1 To 10
C.交换语句S=s+a和a=a*2的顺序
D.同时进行B.C两种修改
下列程序的执行结果为 Private Sub Command1_Click() Dim s1 As String,s2 As String S1;="abcdef" Call Invert(s1,s2) Print s2 End Sub Private Sub Invert (ByVal xstr As String,ystr As String) Dim tempstr As String i=Len(xstr) Do While i>=1 tempstr=tempstr+Mid(xstr,i,1) i=i-1 Loop ystr=tempstr End Sub
A.fedcba
B.abcdef
C.afbecd
D.defabc
单击命令按钮,并在对话框内依次输入99,73,84,88,-1,下列程序段的执行结果为______。 Private Sub Command1_Click() Dim S As Single, max As Single, min As Single n=0 S=InputBox("Please enter a score") max=S min=S Do While S>=0 If S>max Then max=S End If If S < min Then min=S End If S=InputBox("Please enter a score") n=n+1 Loop Print n; ":"; max, min End Sub
A.4:99,88
B.4;99,73
C.4:99,73
D.4;99,88
为使该程序执行结果为10,那么应该在程序划线处填入的语句是()。 #include<iostream> using namespace std; class MyClass { public: MyClass (int a) { x=a; } ___________ //取x值 private: int x; }; int main() { MyClass my(10); cout<<my.GetNum()<<end1; return 0; }
A.return x;
B.int GetNum(){ return x;}
C.intreturn x;
D.void GetNum(){return x;}
[C++代码]
01 inclUde<iostream>
02 using namespace std;
03 class SuperClass {
04 private:
05 int i;
06 publiC:
07 SuperClass()(i=5;)
08 virtual iht getValueO(return i ;)
09 virtual int getSum()=0;
10 };
11 class SubClass:public SuperClass{
12 int J ;
13 public:
14 SubClass(int j):j(0){
15 (1) =j; //用参数j的值更新数据成员
16 };
17 int getValue(){return j;)
18 int getSum(){
19 return (2) getValue()+j;
20 }
21 };
22 void main(void){
23 SuperClass s=new SubClass(-3);
24 cout<<s->getValue()<<"";
25 tout<<s->getSum()<<endl;
26 delete s;
27 }
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