由“For i=1 To 9 Step -3”决定的循环结构被执行() 次。
A.4
B.5
C.6
D.0
- · 有5位网友选择 C,占比26.32%
- · 有3位网友选择 D,占比15.79%
- · 有3位网友选择 C,占比15.79%
- · 有3位网友选择 B,占比15.79%
- · 有2位网友选择 D,占比10.53%
- · 有1位网友选择 A,占比5.26%
- · 有1位网友选择 B,占比5.26%
- · 有1位网友选择 A,占比5.26%
A.4
B.5
C.6
D.0
A.1 To 9
B.9 To 1
C.9 To 1 Step -1
D.1 To 9 Step -1
A.6
B.9
C.5
D.7
Private Sub MoveRight (x() As Integer)
Dim i As Integer
Dim j As Integer
Dim k As Integer
i = UBound (x)
j = x(i)
For k = i To【 】Step -1
【 】
Next k
x(LBeund(x)) = j
End Sub
Private Sub Command1_click()
Dim a(10) As Integer
Dim i As Integer
Dim j As Integer
Dim k As Integer
For i = 0 To 10
a(i) = i
Next i
j = Val(TextText)
k=0
Do
k=k+1
Call MoveRight(A)
Loop Until k = j
For i = 0 To 10
Print a(i);
Next i
End Sub
A、i = 0 To 8
B、i = 1 To 9
C、i = 2 To 10
D、i = 0 To 8 step 2
E、i = 1 To 9 step 2
运行下列语句后,输出的结果是()。 Option Base 1 Dim a i=1 a=Array(l, -2, 9, 0, -1, 9) Do k=a(i) For m = 10 To k Step -2 n=k+m Next m Print n+m i=i+1 Loop While Abs(m+n) <> 27
A.3 27-8
B.3-8 27
C.-8 27 3
D.-8 3 27
当发生Command1_C1ick事件后,以下程序的输出结果是 Private Sub Command1_Click() Dim i As Integer Dim a(10) As Integer For i=9 To 0 Step -1 a(i)=10-i Next i Print a(2);a(5);a(8) End Sub
A.2 5 8
B.7 4 1
C.8 5 2
D.3 6 9
A.3
B.4
C.9
D.10
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