下面程序的输出结果是()。 #include<iostream> Usingnamespacestd; ClassBase{ public:
A.0
B.1
C.01
D.001
A.0
B.1
C.01
D.001
B、3120
C、312
D、3012
下列程序运行结果是 。 #include <iostream.h> class BASE{ char c; public: BASE(char n) { c=n; cout< <c;} }; derived:public base{ char c; public: derived(char n):base(n+1) {c="n;" void main() { derived deri('a');>
include<iostream.h>
voidmain()
{
chara="3":
switch(a)
{
case"3":cout$amp;case"2":cout$amp;default:cout$amp;}
}
A.3
B.321
C.31
D.32
include<iostream.h> void main
{
int num=1:
int&ref=num; ref=ref+2:
cout$amp;}
A.13
B.16
C.36
D.33
include<iostream.h>
ClassA
{
public:A(){cout<<"1";}
~A(){cout<<"2";}
};
ClassB:public:A
{
public:
B(){cout<<"3";}
~B(){cout<<"4";}
};
Voidmain()
{
Bb;
}
A.1234
B.1324
C.1342
D.3142
8、写 出 此 题 的 运 行 结 果 : #include<iostream.h> class Sample { public: void setdata(int n) { i=n; cout<<"i="<<i<<endl; } void setdata(double x) { d="x;" answer">
9、写 出 此 题 的 运 行 结 果 : #include<iostream.h> class Sample { public: Sample(){} Sample(int i){n=i;} Sample &operator=(Sample); void disp(){cout<<"n="<<n<<endl;} private: int n; }; sample &sample::operator="(Sample" s) { sample::n="s.n;" return *this; } void main() s1(10),s2; s2="s1;" s2.disp();>
AAAbBB
BB
CCC
程序如下:
include
void main()
{
char ch[3][4]={"AAA","BB","CCC"},(*q)[4]=ch,*p;
int i;
___________
*p=&39;b&39;;
___________
for(i=0;i<3;i++)
{
cout$amp;}
}
B、30
C、31
D、32
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