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已知某名义长度30m的钢尺的尺长方程式为L=30m+2.8mm+α(t-20℃)×30m,现用该尺在水平地面丈量得AB距离S′=75.000m,AB间的高差为1.5m,丈量时钢尺温度为31℃。则计算得AB距离的水平距离()。
A.75.002m
B. 75.032m
C. 74.968m
D. 74.998m
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- · 有5位网友选择 C,占比55.56%
- · 有2位网友选择 D,占比22.22%
- · 有2位网友选择 A,占比22.22%
A.75.002m
B. 75.032m
C. 74.968m
D. 74.998m
A.75.002m
B.75.032m
C.74.968m
D.74.998m
A.75.002m
B.75.032m
C.74.968m
D.74.998m
A.lt=30+0.007+0.0000125×(t-20℃)×30
B.lt=30-0.007+0.0000125×(t-20℃)×30
C.lt=30+0.010+0.0000125×(t-20℃)×30
D.lt=30-0.010+0.0000125×(t-20℃)×30
A.75.147m
B.75.157m
C.75.142m
D.75.152m
A.75.147m
B.75.157m
C.75.142m
D.75.152m
A.75.147m
B. 75.157m
C. 75.142m
D. 75.152m
在温度t0=+20℃时,将一盘名义长l0=30m的钢尺,与一盘实长(20℃时)为30.005m的标准尺比较,结果的标准尺长为0.003m,求该9尺在+20℃时的实际长度。被钢尺在+20℃时的尺长方程式。
某钢尺的尺长方程式为ιt=30-0.05+1.2×10-5(t-t0)×30m,用该尺以标准拉力在20℃时量得直线长度为54.031m,则该直线的实际长度是()。
(A)54.040m
(B)54.031m
(C)54.022m
(D)54.036m
A.60.074m
B.60.083m
C.60.043m
D.60.037m
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