求 1! + 2! + 3! + ... + n!# include <stdio.h> int main(void) { int n = 0; int i = 0;
求 1! + 2! + 3! + ... + n!# include <stdio.h> int main(void) { int n = 0; int i = 0; int m = 1; int sum=0; printf("请输入n的值:"); scanf("%d", &n); for (i=1;i<=n;++i) { m="m" * i; ____________; } printf ("sum="%d\n",sum);" return 0;>