若arr=np.array([[1,2,3,],[4,5,6,],[7,8,9,]]),则arr[:2,1:]的输出为()。
A.([[2,3],[5,6]])
B.([[1][6]])
C.([[5,6],[8,9]])
D.([[1,2],[4,5]])
A.([[2,3],[5,6]])
B.([[1][6]])
C.([[5,6],[8,9]])
D.([[1,2],[4,5]])
A.rr%2==1
B.arr[arr%2==1]
C.arr[arr/2==1]
D.arr[arr//2==1]
A.arr1=np.array([0,1,2,3,4])
B.arr2=np.array({0:0,1:1,2:2,3:3,4:4})
C.arr3=np.array((0,1,2,3,4))
D.arr1=np.array(0,1,2,3,4)
A.[[1,2],[3,4],[1,2],[3,4]]
B.[[1,2,3,4],[1,2,3,4]]
C.[[1,2],[3,4]]
D.[1,2,3,4,1,2,3,4]
A.a[0:2, :]
B.a[:2, 0:3]
C.a[0:1, 0:2]
D.a[0:2, 0:3]
A.<tf.tensor: id="9," shape="(2,)," dtype="float64," numpy="array([1.," 2.])>
B.<tf.tensor: id="9," shape="(1,2)," dtype="float64," numpy="array([1.," 2.])>
C.<tf.tensor: id="9," shape="(2,)," dtype="float32," numpy="array([1.," 2.])>
D.<tf.tensor: id="9," shape="(2,1)," dtype="float32," numpy="array([1.," 2.])>
A.int[][] arr = new int[3][4]
B.int[][] arr = new int[3][]
C.int[][] arr = new int[][4]
D.int[][] arr = {{1,2},{3,4,5},{6}}
A.int[][] arr = new int[3][4]
B.int[][] arr = new int[3][]
C.int[][] arr = new int[][4]
D.int[][] arr = {{1,2},{3,4,5},{6}}
A.Arr是二维交错数组,共包括9个元素。
B.可以使用Arr[1,2]引用数组中的一个元素。
C.可以使用Arr[1][2]引用数组中的一个元素。
D.由于Arr数组的每个子数组大小不一致,所以必须采用分层创建的方法。
用语言描述下面的程序:using System; public class MikeCat { static void PrintArray(int[,] arr) { for(int i=0;i<4;i++) { for(int j="0;j<2;j++)" console.writeline("arr[{0},{1}]="{2}",i,j,arr[i,j]);" } public static void main() printarray(new int[,]{{1,2},{3,4},{5,6},{7,8}});>
A.3
B.4
C.7
D.8
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