若串S1=‘ABCDEFG’, S2=‘9898’ ,S3=‘###’,S4=‘012345’,执行 concat(replace(S1,substr(S1,length(S2),length(S3)),S3),substr(S4,index(S2,‘8’),length(S2))) 注意:substr(S,i,j)是对字符串S的下标为i开始取j个字符,这里的下标是从0开始的(单选) If the string S1 = 'ABCDEFG', S2 = '9898', S3 = '###', S4 = '012345', execute concat (replace (S1, substr (S1, length (S2), length (S3)), S3), substr (S4, index (S2, '8'), length (S2))) Note substr (S, i, j) is the operation to take string S’s j characters from subscript i. Subscript here is starting from 0.(There is only one correct answer)
A、ABC###G0123
B、ABCD###2345
C、ABCD###1234
D、ABC###G2345