在AM step 2 ,有多少HTRP要被解决呢()
A.10%
B.50%
C.80%
D.90%
A.10%
B.50%
C.80%
D.90%
2. 选词填空(从seat,occupied, return,cooperation 中选择合适的词填空) 对话情景为:A passenger takes a wrong seat. CA: Excuse me, Sir. Would you please step aside and allow the other passengers to go through? PAX1: Oh. This is my 1 . It is 2 by others. CA: Yes, would you allow me to talk with the passenger? PAX1: Yes, please. (to Pax 1) CA: I am sorry, but you are taking the wrong seat. May I ask you kindly to 3 to your original seat? PAX2: Really? Oh, I am sorry about that. CA: Thank you for your 4 . (to Pax 2) CA: Sir, I have talked with that passenger. She has already returned to her own seat. PAX1: Thanks for your helping. CA: You are welcome. 请选择第四个空的正确答案。
In a Delta Modulation (DM) system, A sinusoidal test signal of amplitude Am=1(V) and frequency fm = 1 (kHz) is applied to the system. The sampling rate is fs = 8 (kHz) ,to avoid slope overload, the step size Δ is at least (V).
A、0.125
B、0.785
C、1.57
D、0.3925
阅读以下说明,回答问题1至问题3,将答案填入答题纸对应栏内。
【说明】
在某嵌入式处理器上,编写以下两段秸序(编译选项中,存储采用4字节对齐方式)。
程序段1:
struct studentl {
char name [10] ;
long sno;
char sex;
float score [4] ;
*pl, al, bl;
程序段2:
union student2 {
char name [10] ;
long sno;
char sex,
float score [4] ;
*p2, a2, b2;
汉诺塔问题说明:有n个盘子在A处,盘子从小到大,最上面的盘予最小,程序要
把这n个盘子从A处搬到C处,可以在E处暂存,但任何时候都不能出现大的盘子压
在小的盘子上面的情况。
下列是一段求解汉诺塔问题的C语言程序。
include <stdio . h>
void move (int n, char a, char c)
{
static int Step=l;
printf ("Step %2d: Disk %d %c..--> %c\n", Step, n, a, c) ;
Step++;
}
void Hanoi (int n, char a, char b, cnar c)
{
if (n>l)
{
Hanoi (n-l, a, c, b) ;
move (n, a. c) ;
Hanoi (n-l, b, a, c) ;
}
else move (n,a,c);
}
void main()
{
Hanoi(3, ’A’, 、B’, 、C ’);
}
【问题1】(3分)
C语言函数的一般格式为:
<函数类型> <函数名> (<参数列表>)
{
<函数体>;
}
简答下述问题,将答案填写在答题纸中对应栏目。
(l)<函数类型>的含义是什么?
(2)<参数列表>的含义是什么?
(3)C语言函数之间的参数如何传递?
【问题2] (6分)
回答问题,将答案填写在答题纸中对应栏目。
(1)sizeof(struct studentl)结果是多少
(2) sizeof(union student2)结果是多少
(3)变量a2在程序段2中定义,写出执亍以下语句后的输出结果。
strcpy (a2. name,¨zhangwei¨);
a2.sex=’f’;
printf ("%s¨, a2 .name);
【问题3](6分)
仔细阅读求解汉诺塔问题的C语言程序,完成其中(1)~(4)空白填空,将答案
填入答题纸的对应栏内。
运行结果为:
Step1:Disk l A---->C
Step 2: (l)
Step 3: Disk I C---->B
Step4: (2)
Step 5: (3)
Step 6: Disk 2 B---->C
Step 7: (4)
设某AM信号电压uAM(t)=2[1+0.6cos(4000πt)]cos(6π×106t)(V),其载波频率是多少?调制信号频率是多少?调幅度为多少?
A.b1 * 2 + b2 / 2 = 60
B.b1 * 2 = b2 / 2
C.b1 / 2 + b2 * 2 = 60
D.b1 - b2 = 60
A.x=x+1
B.x=x+i
C.x=x+i+1
D.x=x*2
A.15
B.25
C.35
D.45
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