It's 4:30 . The students in Class 2 are in the classroom. Li Lei and Jim take off their co
What time is it now?
A.3:50.
B.4:30.
C.5:30.
What time is it now?
A.3:50.
B.4:30.
C.5:30.
struct stud
{char num[6];
int s[4];
double ave=0.0;
}a;
main()
{int i;
for(i=0;i<4;i++)scanf("%d",&a.s[i]);
for(i=0;i<4;i++)a.ave+ =a.s[i];
printf("%f",a.ave);
}
错误:______
改正:______
参考答案:错误
设有以下结构类型说明和变量定义,则变量a在内存所占字节数是______。
Struct stud
{ char hum[6];
int s[4];
double ave;
} a,*p;
Cruise Itinerary Highlights
* 24-hour room service
- Fine dining
- Fully-equipped health spa
- Live music and comedy shows
- Fitness classes
- Adventure Ocean youth activities
- Port-of-call lectures
- Creative theme parties
- Top 40 and Big Band lounges
- Casino with Caribbean stud poker
- Cooking demonstrations
- Broadway/Las Vegas-style. entertainment
- Thousands of balcony cabins
- Sumptuous midnight buffets
- Up to a dozen bars and lounges
- Rock climbing wall, some ships
- Ice skating rink, some ships
- Johnny Rocket's 50's dinner, some ships
10-day Europe - Northern cruise aboard Cruise Itinerary
Day Ports of Call Arrival Departure
1 Copenhagen --- 11:00
2 At Sea --- ---
3 Stockholm 7:00 a.m. 5:30 p.m.
4 Helsinki 8:30 a.m. 5:00 p.m.
5 St. Petersburg 6:30 a.m. ---
6 St. Petersburg --- 5:30 p.m.
7 Tallinn 7:00 a.m. 1:00 p.m.
8 Gdansk 10:00 a.m. 7:00 p.m.
9 At Sea --- ---
10 Oslo 7:00 a.m. 1:00 p.m.
11 Copenhagen 5:00 a.m. 1:00 p.m.
Which service is NOT provided on some ships?
A.Fully-equipped health spa.
B.Fitness classes.
C.Rock climbing wall.
D.Sumptuous midnight buffets.
A、Dim S As Stud Stud.no=0201 Stud.name= "王进" Stud.score=78,88,97
B、Dim S As Stud S.no=0201 S.name= "王进" S.score=78,88,97
C、Dim S As Stud Stud.no=0201 Stud.name= "王进" Stud.score(1)=78 Stud.score(2)= 88 Stud.score(3)= 97
D、Dim S As Stud S.no=0201 S.name= "王进" S.score(1)=78 S.score(2)= 88 S.score(3)= 97
如下程序段定义了学生成绩的记录类型,由学号、姓名和三门课程成绩(百分制)组成。 TYPE STUD NO AS INTEGER NAME AS ATRING SCORE(1 TO 3) AS SINGLE END TYPE 若对某个学生的各个数据项进行赋值,下列程序段中下确的是
A.DIM S AS STUD STUD. NO=1001 STUD. NAME="舒宜" STUD. SCORE=78,88,96
B.DIM S AS STUD S. NO=1001 S. NAME="舒宜" S. SCORE=78,88,96
C.DIM S AS STUD STUD. NO=1001 STUD. NAME="舒宜" STUD. SCORE(1)=78 STUD. SCORE(2)=88 STUD. SCORE(3)=96
D.DIM S AS STUD S. NO: 1001 S. NAME="舒宜" S. SCORE(1)=78 S. SCORE(2)=88 S. SCORE(3)=96
如下程序段定义了学生成绩的记录类型,由学号、姓名和三门课程成绩(百分制) 组成。 Type Stud No As Integer name AS String score(1 to 3) As Single End Type 若对某个学生的各个数据项进行赋值,下列程序段中正确的是______。
A.Dim S As Stud Stud.no=1001 Stud.name=“舒宜” Stud.score=78,88,96
B. Dim S As Stud S.no=1001 S.name=“舒宜” S.score=78,88,96
C. Dim S As Stud Stud.no=1001 Stud.name=“舒宜” Stud.score(1)=78 Stud.score(2)=88 Stud.score(3)=96
D. Dim S As Stud S.no=1001 S.name=“舒宜” S.score(1)=78 S.score(2)=88 S.score(3)=96
class Student {public: Student(int n,float s):num(n),score(s){} void change(int n,float s) {num=n;score=s;} void display() {cout<<num<<" private: int num; float score; }; main() {student stud(101,78.5); student *p="&stud;" stud.display(); stud.change(101,80.5); p->display(); return 0;} 将main函数中第二句改为const Student *p=&stud;在上面程序的基础上修改程序,使之能正常运行。(提示:可以把非法的语句删掉,改另一种方式调用对应的成员函数)
A.pt->show ()
B.t.show()
C.t.set()
D.(*pt). show ()
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