下面程序运行的结果是() class FatherClass { int[] thenArray = new int[] { 1,2,3,4 }; publi
#include
int main()
{
int i;
for(i=0;i<3;i++)
switch(i)
{
case 0: printf("%d",i);
case 2: printf("%d",i);
default: printf("%d",i);
}
return 0;
}
A.022111
B.012
C.000122
D.021021
A、lst=[[1, 2, 3], [4, 5]]
B、tup=(1, 2)
C、lst=[1, "python", [2, 3, 4]]
D、tup=(1)
A、slip stream
B、slipstream stream
C、stream slip stream
D、slipstream slip stream
#include <iostream.h> class Base { protected: //① int Base_pro; public: void set(int i) { Base_pro=i; } }; class Derived : public Base //② { int Drv_pri; public: void DrvSet(int i, int j) { Drv_pri=i; set(j); //③ } void display() { cout<<""\ndrv_pri drv_pri; base_pro; ④ } }; void main() { derived d; d.drvset(3,6); d.display(); 对于上述程序,如果将第①句中的“protected:”去掉,则编译时()> A、第③、④两句都出错
B、第③句出错,第④句对
C、第③句对,第④句出错
D、第③、④两句都对
declare @e numeric(5,2)
declare @ c1 int, @ c2 int, @ c3 int, @ c4 int
set @ c1=0; set @ c2 =0; set @ c3=0; set @ c4=0
declare xxx cursor
for select 成绩 from score
open xxx
fetch xxx into @ c
while @'@ fetch_status = 0
begin
if(@c > =90) set @cl =@ e1 +1;
else if(@ c > =70) set @ c2 =@ c2 +1;
else if(@ c> =60) set @ c3 =@ c3 +1;
else set @ c4 = @ c4 + 1
fetch from xxx into @ c
end
close xxx
deallocate xxx
print 优秀生人数:'+sb(@ c1,5);
print食好生人数:'+str(@ c2,5);
print及格生人数:'+str(@ c3,5);
print及格生人数:'+sh(@ c4,5)
为了保护您的账号安全,请在“简答题”公众号进行验证,点击“官网服务”-“账号验证”后输入验证码“”完成验证,验证成功后方可继续查看答案!